questions a bit vague but if you leave the hairdryer on for 1 hour then it uses 1.2 kWh. ( assume that this is the actual load and not the load prior to efficiency)
nb kVAh is similar to kWh but phase angle voltage to current causes an increase in the power consumtion (power factor usually nominal in the region of 0.8-0.95 (kVA=kW/pf) in the case of a hair dryer then this is negligible ie 1 (unity)A 304/kwh, what does it cost to generate the 1200-w hair dryer for 1 h?
Your question is a bit confusing, but I'm assuming you mean 1KWh costs 304 units (cents?). Leaving a 1200W hair dryer on for 1 hour consumes 1.2KWh. This means:
1.2*304=364.8 units.
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